PGA TourNovember 6, 2016

Shriners: Pampling shoots 65, wins by 2

LAS VEGAS, NV - NOVEMBER 06:  Rod Pampling of Australia reacts after chipping in on the eighth hole during the final round of the Shriners Hospitals For Children Open on November 6, 2016 in Las Vegas, Nevada.  (Photo by Steve Dykes/Getty Images)
Getty ImagesLAS VEGAS, NV - NOVEMBER 06: Rod Pampling of Australia reacts after chipping in on the eighth hole during the final round of the Shriners Hospitals For Children Open on November 6, 2016 in Las Vegas, Nevada. (Photo by Steve Dykes/Getty Images)

Rod Pampling, 47 and more than a decade removed from his last PGA Tour victory, birdied four of his last six holes and won the Shriners Hospitals for Children Open at the TPC Summerlin in Las Vegas on Sunday.

Pampling took the lead when Lucas Glover bogeyed the 17th hole, then won by two when he holed a 30-foot birdie putt on 18 for his first victory since winning the Bay Hill Invitational in 2006.

“It’s extremely rewarding,” the Australian said. “Obviously, winning Arnold Palmer’s event in ’06 is still on top, but coming back from what we’ve had the last few years to get a win under the belt is phenomenal and amazing. It’s a great feeling.”

Pampling, who opened the tournament with a 60 and entered the final round a stroke behind Glover, finished with a seven-under par 65, two ahead of Brooks Koepka and three ahead of Glover, who bogeyed his final two holes.

Italy’s Francesco Molinari, who closed with a 61, tied for fourth, along with Geoff Ogilvy and Harris English.


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